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Does cast between signed and unsigned int maintain exact bit pattern of variable in memory?
做演员之间签署的和无符号整型变量在内存中保持精确的比特模式?
整型的每一种都有无符号(unsigned)和有符号(signed)两种类型(float和double总是带符号的),在默认情况下声明的整型变量都是有符号的类型(char有点特别),如果需声明无符号类型的话就需要在类型前加上unsigned。
无符号整数
Does cast between signed and unsigned int maintain exact bit pattern of variable in memory?
做演员之间签署的和无符号整型变量在内存中保持精确的比特模式?
整型的每一种都有无符号(unsigned)和有符号(signed)两种类型(float和double总是带符号的),在默认情况下声明的整型变量都是有符号的类型(char有点特别),如果需声明无符号类型的话就需要在类型前加上unsigned。